# Line slope calculator 2x-5y=-9

**Straight line given by points A[3; 3] and B[8; 5]**

## Calculation:

**Slope-intercept form of line:**y = 0.4x+1.8

**Canonical form of the line equation:**2x-5y+9 = 0

**Parametric form of the line equation:**

x = 5t+3

y = 2t+3 ; t ∈ R

**Slope:**m = 0.4

**Slope angle of line: φ =**21°48'5″ = 0.3805 rad

**X intercept:**x

_{0}= -4.5

**Y intercept:**y

_{0}= q = 1.8

**Distance line from the origin:**d

_{0}= 1.6713

**The length of the segment AB: |AB| =**5.3852

**Vector: AB =**(5; 2)

**Normal vector: n =**(2; -5)

**Midpoint of the segment AB: M =**[5.5; 4]

**Perpendicular Bisector equation:**5x+2y-35.5 = 0

**Vector OA = (3; 3) ; |OA| = 4.2426**

**Vector OB = (8; 5) ; |OB| = 9.434**

**Scalar product OA .OB = 39**

**Angle ∠ AOB = 12°59'41″ = 0.2268 rad**